10x^2-49x+20=10x-x^2

Solution for 10x^2-49x+20=10x-x^2 equation:

10x^2-49x+20=10x-x^2

We move all terms to the left:

10x^2-49x+20-(10x-x^2)=0

We get rid of parentheses

10x^2+x^2-10x-49x+20=0

We add all the numbers together, and all the variables

11x^2-59x+20=0

a = 11; b = -59; c = +20;
Δ = b2-4ac
Δ = -592-4·11·20
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-51}{2*11}=\frac{8}{22}
=4/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+51}{2*11}=\frac{110}{22}
=5
$